Does it imply make \$x\$ the topic?  Great inquiry. This is an expression carapeastra.netematicians and also carapeastra.netematics educators utilize a whole lot, as well as it has a particular implying that isn"t completely clear to the student.

Idiomatically talking, to create a feature "in regards to" a provided variable or variables implies to create an algebraic expression making use of just that variable or variables.

So for example, provided a formula \$x +2 y-3z = 0\$, we can resolve for \$z\$ in regards to \$x\$ and also \$y\$ as \$z=\ frac 1 (x +2 y)\$.

Essentially talking, terms are the items that make up an expression. So in the expression \$8x ^ 2-8x\$, \$8x ^ 2\$ as well as \$8x\$ are terms incorporated by the reduction feature. The expression is in regards to \$x\$ because each term in the expression has just the variable \$x\$ (as well as constants) in it. When it implies

share in regards to \$x\$

It indicates to reveal the amount you"re searching for in regards to \$x\$, the variable.

Consequently,

Considering that:

\$\$f(x) = 2x ^ 2 + 4x\$\$

So,

\$\$f(-2 x) = 2(-2 x)^ 2 + 4(-2 x) = 8x ^ 2 - 8x\$\$ It implies discover the feature \$g(x) = f(-2 x)\$ as if everyobody that recognizes carapeastra.net can merely connect in any type of worth of \$x\$ to locate \$g(x)\$.

As an example, if \$f(x) = \ transgression(x)\$, then \$f(-2 x) = \ wrong(-2 x)\$, and even far better (constantly streamline if that is feasible!) \$\ wrong(-2 x)=-\ transgression(2x)\$ is the expression you are trying to find. To examine \$f(-2 x)\$, you will certainly initially calculate \$x"=-2 x\$, then \$2x"^ 2 +4 x"\$.

You are asked to get rid of the intermediate replacement action as well as think of a straight expression \$g(x)=f(-2 x)\$.

Clearly, \$g(x)=f(-2 x)=2(-2 x)^ 2 +4(-2 x)=8x ^ 2-8x\$, which is the response.

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